Answer:
not possible.
Step-by-step explanation:
number of invitations luanne has to address after x days = 120-15x
number of invitations Darius has to address after x days = 120 + 15(7-x)
so, if the number of invitations should be the same for both of them,
we have to equate their number of invitations
120-15x = 120 + 15(7-x)
subtracting 120 from both the sides,
-15x = 15(7-x) = 105 -15x
adding we 15x on both sides, we wont find any solution for x.
so, this isnt possible or the question must be wrong.
Answer:
dependent events since P(A and B) is not equal to P(A) * P(B)
Step-by-step explanation:
According to the Question,
- Given, The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballgame (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52.
Thus, The events A, B and A∩B are:
A - Jane will go to a ballgame on Monday;
B - Kate will go to a ballgame on Monday;
A∩B - Kate and Jane both go to the ballgame on Monday.
- P(A)=0.73, P(B)=0.61, P(A∩B)=0.52.
- Pr(A)⋅Pr(B) = 0.73⋅0.61 = 0.4453 ≠ 0.52
So, events A and B are dependent events since P(A and B) is not equal to P(A) * P(B)
Answer:
8a+5b-9
Step-by-step explanation:
(8a+2b-4)+(3b-5)
8a+2b+3b-4-5
8a+5b-9
Answer:
C) P=56cm^2
Step-by-step explanation:
P=(a*h)/2 a=14, h=8
P=(14*8)/2
P=112/2
P=56
Answer:
Step-by-step explanation: