There is a 20 percent chance of choosing a number that would fit the requirements of both a and b this si because only 1 and three are odd and less than three so 2/10 is twenty percent
Answer:
Step-by-step explanation:
Given
Required
Represent as an equation;
Expand the above
<em>Recall that b = $10 ----given</em>
becomes
12x - 56 = y. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)
Answer:
Number 4 will be Quadrant 3
Number 5 will be Quadrant 1
Number 6 will be 3 -4
Step-by-step explanation:
For number 6 it says a point so that is what I did sorry if i`m wrong
Answer:
there would be a 1-51 chance most likely
Step-by-step explanation:
