Answer:
153
Step-by-step explanation:
If the table adds up to 20 and opened toe counts for 45% of the total. then 45% of 340 is 153 !
Significant figures refers to digits within a number which must be included in other depict correct quantity of the figure.
- 4.29478416 = 4.2947842 ( 8 significant figures)
- 4.29478416 = 4.29478 (6 significant figures)
- 4.29478416 = 4.295 ( 4 significant figures)
- 4.29478416 = 4.3 (2 significant figures)
To round a number to a certain number of significant figures,
- Only leading 0 which comes before the decimal Point are regarded as insignificant.
- Once the number of significant figures have been identified, the next number after this is either rounded up to 1 and added to the last value(if number is ≥5) or rounded to 0 (if number is less than 5)
Learn. More : brainly.com/question/13386983?referrer=searchResults
It represents the entire data set and the triangles inside the circle graph represent part of the whole data set
<span>sinx - cosx =sqrt(2)
Taking square on both sides:
</span>(sinx - cosx)^2 =sqrt(2)^2<span>
sin^2(x) -2cos(x)sin(x) + cos^2(x) = 2
Rearranging the equation:
sin^2(x)+cos^2(x) -2cos(x)sin(x)=2
As,
</span><span>sin^2(x)+cos^2(x) = 1
</span><span>So,
1-2sinxcosx=2
1-1-2sinxcosx=2-1
-</span><span>2sinxcosx = 1
</span><span>Using Trignometric identities:
-2(0.5(sin(x+x)+sin(x-x))=1
-sin2x+sin0=1
As,
sin 0 = 0
So,
sin2x+0 = -1
</span><span>sin2x = -1</span><span>
2x=-90 degrees + t360
Dividing by 2 on both sides:
x=-45 degrees + t180
or 2x=270 degrees +t360
x= 135 degrees + t180 where t is integer</span>
Answer:
a. 0.689
b. 0.8
c. 0.427
Step-by-step explanation:
The given scenario indicates hyper-geometric experiment because because successive trials are dependent and probability of success changes on each trial.
The probability mass function for hyper-geometric distribution is
P(X=x)=kCx(N-k)C(n-x)/NCn
where N=4+3+3=10
n=2
k=4
a.
P(X>0)=1-P(X=0)
The probability mass function for hyper-geometric distribution is
P(X=x)=kCx(N-k)C(n-x)/NCn
P(X=0)=4C0(6C2)/10C2=15/45=0.311
P(X>0)=1-P(X=0)=1-0.311=0.689
P(X>0)=0.689
b.
The mean of hyper-geometric distribution is
μx=nk/N
μx=2*4/10=8/10=0.8
c.
The variance of hyper-geometric distribution is
σx²=nk(N-k).(N-n)/N²(N-1)
σx²=2*4(10-4).(10-2)/10²*9
σx²=8*6*8/900=384/900=0.427