Answer:
Acetylide , Enol ,aldehydes, tautomers, alkynes , Hydroboration, Keto
Explanation:
Reset <u>Acetylide</u> anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. <u>Enol </u>tautomers have an O-H group bonded to a C=C. <u>aldehydes </u>are formed from terminal alkynes with the addition of water using BH3 then H2O2. <u>tautomers</u> are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. <u>alkynes</u> are compounds that contain a carbon-carbon triple bond. <u>Hydroboration</u> of a terminal alkyne adds BH₂ to the less substituted, terminal carbon.<u> Keto</u> tautomers have a C=O and an additional C-H bond.
Answer:
C1V1=C2V2
C1 is 2.0mol/l
V1=?
C2=.4mol/L
V2=100ml or for this 0.1L
V1 is 20ml
Best way to prepare this is to measure out 20ml of the 2 molar solution and add 80mL to it to get to 100mL
Explanation:
Carbon is located in the fourth group, second period. It is also in the nonmetal section of the table as well