Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Answer:
Probability = 0.12025
Step-by-step explanation:
P (Am) = 1/50 = 0.02 {Magazine ad}
P (At) = 1/8 = 0.125 {Television ad}
P (Am ∩ At ) = 1/100 = 0.01 {Both ads}
P (Am U At) = P (Am) + P (At) - P (Am ∩ At )
= 0.02 + 0.125 - 0.01
P (Am U At) = 0.135 {Person sees either ad}
P (Am' ∩ At') = 1 - P (Am U At)
P (Am' ∩ At') = 1 - 0.135 = 0.865 {Person sees none ad}
Prob (Purchase) = Prob (Purchase with ad) + Prob (purchase without ad)
P (P/ A) = 1/4 = 0.25 , P (P / A') = 1/10 = 0.1
P (P) = (0.25) (0.135) + (0.1) (0.865)
= 0.03375 + 0.0865
0.12025
Answer:
at first we put the numbers in order from least to greatest
2 , 6 , 6 , 7 , 8 , 9
1st quartile = 6
median = (6+7)/2 = 6.5
3rd quartile = 8