Step-by-step explanation:
ABC be the given isosceles right triangle such that <B = 90° , side AC is the hypotenuse; and, AB= BC
Then, (AB)^2 + (BC)^2 = (AC)^2…. Pythagoras theorem.
(AC)^2 = 98 sq. cm. ( given)
So, (AB)^2 + ((BC)^2 = 98
But, AB = BC = a ( say) …. ( given)
Therefore, a^2 + a^2 = 98
Or, 2a^2 = 98.
So, a^2 = 98 / 2 = 49
Hence, a = AB = BC = √49 = 7 cm.
The side AC ( the hypotenuse) = √98 = √(7 *7*2)
= 7 *√2 = 7* 1.414 = 9..898cm., say, 9.9 cm.
Hence, the three sides of the right isosceles triangle are 7 cm, 7cm and ~ 9.9 cm. Answer
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