Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
Answer:
D.)
/
Step-by-step explanation:
The solution is (5,2)
Step-by-step explanation:
From the third column the equation for sum of equivalent system is given as;
8x = 40
divide both sides by 8 to get value of x
8x/8 = 40/8
x=5
Using the value of x in the fifth column's first equation will be;
4x +4y =28
4(5) + 4y =28
20 +4y =28
4y= 28-20
4y=8
divide both sides by 4 to get y
4y/4 =8/4
y=2
The solution is x=5 and y=2 written as (5,2)
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Solving simultaneous equations : brainly.com/question/12647791
Keywords: table, solution, column, original system
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2x+15x you can just switch the two.
I hope this helps you
x^2+4x+3=2x+6
x^2+2x-3 =0
x +3
x -1
(x+3)(x-1)=0
x+3=0 x= -3
x-1=0 x=1