Answer:
the answer in factor form would be
-3(
Factors of 121 are; 1,11, and 121. so it would be D.
Answer:
The angle between the ramp and the horizontal is 11.54 degrees
Step-by-step explanation:
Here, we want to get the angle between the ramp and the horizontal
What we have to do here is to bring the measure of 2 m near to the edge leftwards, so we can have a right triangle
Now, the angle we want to calculate is the angle that faces the measure 2 m
The given measure of 10 m will represent the hypotenuse of the right triangle
The trigonometric ratio that links the hypotenuse and the opposite is the sine
The sine is the ratio of the opposite to the hypotenuse
Thus, we have it that;
sin theta = opp/hyp
sin theta = 2/10
sin theta = 0.2
theta = sin^-1 0.2
theta = 11.54
Answer:
-9
Step-by-step explanation:
The applicable exponent rule is ...
a^b·a^c = a^(b+c)
___
For the y factor, ...
y^-13 · y^4 = y^(-13+4) = y^-9 . . . . . exponent of -9
Answer:
In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
Also:
The normal distribution is symmetric, which means that 50% of the data is above the mean and 50% is below.
Then:
In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.
