Answer:
The empirical formula=CHO. To explain it is C1H1O1 but we don't put the one that's why it is CHO
Explanation:
Answer:
Explanation:
By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.
The neutralization reaction that you are studying is the acid-base reaction:
- HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)
Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:
- Half molarity = M / 2 = 0.2 M / 2 = 0.1 M
So, the answer is the first choice: a. 0.1 M.
The binding energy in MeV per atom is - 63284.56 Mev.
The amount of energy needed to detach a particle from a system of particles or to disperse every particle in the system is known as the binding energy. Subatomic particles in atomic nuclei, electrons attached to atom's nuclei, and atoms and ions bonded together in crystals are three examples of where binding energy is very relevant.
If we have a nucleus with Z protons and N neutrons and mass MA, where A = Z + N then its binding energy in MeV is given by: Eb(MeV) = (Zmp + Nmn - MA) x 931.494 MeV/u
Mass of atom = 69.955264 amu
Mass of proton = 1.007825 amu
Mass of neutron = 1.008665 amu
Binding energy, Mev = (Zmp + Nmn - M) × 931.494MeV/u
= ( 1.007825 + 1.008665 - 69.955264) × 931.494
= - 67.938774 × 931.494
= - 63284.56 Mev
Therefore, the binding energy in MeV per atom is - 63284.56 Mev.
Learn more about binding energy here:
brainly.com/question/16795451
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Answer:
D. Na2O
Because we already know that sodium oxide is a binary ionic compound because it contains one metal cation and one non-metal anion.
When an electron occupies an orbital of an atom singly, rather than an electron pair such electron is said to be an unpaired electron. Each atomic orbital of an atom specified by quantum numbers can contain a maximum of two electrons having opposite spins, electron pair.
The numbers of unpaired electrons are determined by the electronic configuration of an atom. The electronic configuration of calcium, 
is:
or ![[Ar]4s^{2}](https://tex.z-dn.net/?f=%5BAr%5D4s%5E%7B2%7D)
Since, from the electronic configuration it is clear that the number of electrons in valence orbital that is 
is 2 that means the electrons are paired up in the valence orbital so, there are no unpaired electrons present in .
Hence, the number of unpaired electrons in is 0.
