Answer:
The answer to your question is 160 g of Fe₂O₃
Explanation:
Data
mass of Fe = 112 g
mass of CO = in excess
mass of Fe₂O₃ = ?
Balanced chemical reaction
Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂
Process
1.- Calculate the molar mass of Fe₂O₃ and Fe
Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g
atomic mass of Fe = 56
2.- Use proportions to calculate the mass of Fe₂O₃ needed
160 g of Fe₂O₃ ------------------- 2(56) g of Fe
x g of Fe₂O₃ ------------------ 112 g of Fe
x = (112 x 160) / 2(56)
x = 17920/112
x = 160 g of Fe₂O₃
<u>Answer:</u>
<u>For A:</u> The for the given reaction is
<u>For B:</u> The for the given reaction is 1642.
<u>Explanation:</u>
The given chemical reaction follows:
The expression of for the above reaction follows:
We are given:
Putting values in above equation, we get:
Hence, the for the given reaction is
Relation of with is given by the formula:
where,
= equilibrium constant in terms of partial pressure =
= equilibrium constant in terms of concentration = ?
R = Gas constant =
T = temperature = 500 K
= change in number of moles of gas particles =
Putting values in above equation, we get:
Hence, the for the given reaction is 1642.
Answer:
m H2O = 56 g
Explanation:
∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:
⇒ - (mCΔT)Al = (mCΔT)H2O
∴ m Al = 25.0 g
∴ Mw Al = 26.981 g/mol
⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al
⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C
⇒ Q Al = 1327.64 J
∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C
⇒ mH2O = 55.722 g ≅ 56 g
Answer is: B. C(s) + 2S(s) + 89.4 kJ → CS2(l).
Missing question:
A. C(s) + 2S(s) → CS2(l) + 89.4 kJ.
B. C(s) + 2S(s) + 89.4 kJ → CS2(l).
C. C(s) + 2S(s) + 89.4 kJ → CS2(l) + 89.4 kJ.
D. C(s) + 2S(s) → CS2(l).
Because enthalpy of
the system is greater that zero, this is endothermic reaction (<span>chemical reaction that
absorbs more energy than it releases)</span>, heat is included as a reactant.
Answer:
The answer is
<h2>32 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume = 40 mL
density = 0.80 g/mL
The mass is
mass = 40 × 0.8
We have the final answer as
<h3>32 g</h3>
Hope this helps you