Answer:
Use the Pythagorean theorem for right triangles to solve this
a^2 + b^2 = c^2 where 'a' and 'b' are the legs of the triangle and 'c' is the hypotenuse
so:
8^2 + b^2 = 17^2 solve for the second leg, b
64 + b^2 = 289
b^2 = 289 - 64= 225
b = 15
Answer:(a=5,b=3)
7a-3b = 26--------(1)
a + 2b =11---------(2)
on mutlplying by7 in eq 2
= 7a+14b=77-------(3)
from eq(1) and (3) (on substracting)
7a+14b=77
7a-3b=26
________
=-17b=51
b=51/17
b=3
on putting value of b in eq 1
7a-3b = 26
=7a-9=26
7a=35
a=5
Step-by-step explanation:
hope it helps
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Answer:
See Explanation
Step-by-step explanation:
Given
The attached graph
Required
Point on the line
The options are not given. So, I will provide general answers.
To do this, we simply write out the coordinates that lie on the line.
Some of them are:
Answer: 82
Step-by-step explanation:
59+23=82
Check
82-23=59
