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2 years ago

PLEASE HELP ASAP FIND THE LENGTH

Mathematics

1 answer:

Bond [772]2 years ago

5 0

Triangle ABC:
<ABC=90°
<ACB=y

Triangle CDE:
<CDE=90°
<DCE=y

The two triangles have two congruent angles, then they are similars, and theirs sides must be proportionals:

Adjacent angle to y / Hypotenuse

Triangle CDE Triangle ABC
CD/CE = BC/AC

Replacing the values:
x/7=(20-x)/21

Solving for x. Cross multiplication:
(21)(x)=(7)(20-x)
21x=140-7x
21x+7x=140-7x+7x
28x=140
28x/28=140/28
x=5

Length of CD = x = 5

Answer: The length of CD is 5

Answer: 5

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Suzie solved a linear equation for y. This equivalent equation was her result. y = 7x + 23 Which equations could have been the l

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Answer:

2, 3, 5

Step-by-step explanation:

The question asking for the linear equation Suzie manipulated. The answer should be equal to the starting equation. So, we just need to manipulate the option to y= mx + c format.

1. y + 7x = 23

y= -7x +23 (false)

2. . –7x + y = 23

y= 7x + 23 (true)

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2y= 14x+ 46

y= 7x +23 (true)

4. y – 7x = –23

y= 7x - 23 (false)

5. 7x – y = –23

-y= -7x -23

y= 7x + 23 (true)

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2 years ago

I need help... how to simplify this ?

valentina_108 [34]

Answer:

$b^{2} \sqrt{30b}$

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

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2 years ago

Read 2 more answers

A) y=1.1x+23 B) y=1.25x+20 C) y=1.25+40.67 D)y+1.4+40.67

Lunna [17]

Answer:

I believe C is the correct answer because the graph starts above 40 on y axis and D is incorrect because of the y + not y=

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2 years ago

Describe the graph of y={1/(2x-10)}-3 compared to the graph of y=1/x

tester [92]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
\\\\
f(x)= A\sqrt{ Bx+ C}+ D
\\\\
f(x)= A(\mathbb{R})^{ Bx+ C}+ D
\\\\
f(x)= A sin\left( B x+ C \right)+ D
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if } B\textit{ is negative}$

$\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind, let's check these two

$\bf \stackrel{parent}{y=\cfrac{1}{x}}\qquad \qquad\qquad \qquad \stackrel{transformed}{y=\cfrac{1}{\stackrel{B}{2}x\stackrel{C}{-10}}\stackrel{D}{-3}}\\\\
-------------------------------\\\\
B=2\qquad \textit{shrinks horizontally by }\frac{1}{2}
\\\\\\
C=-10\qquad \cfrac{C}{B}=\cfrac{-10}{2}\implies -5\qquad \textit{horizontally right-shifted by }5
\\\\\\
D=-3\qquad \textit{vertically down-shifted by }3$

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2 years ago

What are the values of x in the equation 4x^2+4x-3=0

ludmilkaskok [199]

I have an answer and an explanation!

ANSWER: $X=\frac{1}{2} (or) x= \frac{-3}{2}$

Explanation:

{Let's solve your equation step-by-step.}
 $4 x^{2} +4x-3=0$

{Step 1: Factor left side of equation.}
 $(2x-1)(2x+3)=0$

{Step 2: Set factors equal to 0.}
 $2x-1=0 (or) 2x+3=0$

3 0

2 years ago