A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer: C) 163
Step-by-Step Solution:
In the Right Triangle formed to the extreme right, lets mark the angles as
∠1, ∠2 and ∠3.
Therefore, from the Figure :-
∠1 = 73°
∠2 = 90°
By Angle Sum Property :-
∠3 = 180 - (73 + 90)
∠3 = 180 - 163
=> ∠3 = 17°
The Angle which forms a Linear Pair with ∠3 is the Corresponding Angle of ∠r, and Corresponding Angles are Equal.
Therefore,
=> 180 - ∠3
= 180 - 17
=> 163°
Therefore, the Angle that forms the Linear Pair with ∠3 is 163°
This Angle is Corresponding to ∠r and hence they are Equal ie. ∠r = 163°
Hence, ∠r = 163°
Answer:
Step-by-step explanation:
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.
a) Let X represent the price of the option
<h3><u> x P(X=x)
</u></h3>
$1000 20/100 = 0.2
$200 50/100 = 0.5
$0 30/100 = 0.3
b) Expected option price
Therefore expected gain = $300 - $150 = $150
c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.
1/8 is a fraction to represent 12.5%
