I believe the answer is a sorry if i am incorrect
we are given
6 × 8 = 48
we know that
commutative property of multiplication:
now, we will verify each options
option-A:
we have
6 × 8 = 48
now, we can find it's commutative
so, we get
8 × 6 = 48
so, this is TRUE
option-B:
we have
6 × 8 = 48
now, we can find it's commutative
so, we get
8 × 6 = 48
so, this is FALSE
option-C:
we have
6 × 8 = 48
now, we can find it's commutative
so, we get
8 × 6 = 48
so, this is FALSE
Answer:
See explanation
Step-by-step explanation:
In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.
Consider triangles DIH and EGH. In these triangles,
- as alternate interior angles;
- as vertical angles;
- because point H bisects segment DE (given).
Thus,
by AAS postulate
Answer:
Time it will take to drain the entire tower = 2.8minutes
Step-by-step explanation:
The question is incomplete as the volume of the tower was not indicated.
Let's consider the following question:
If there are 7.48 gallons in a cubic foot, and the volume of the tower is around 36000in cubed. Residents of the apartment building are using the water from the tower at an average rate of 56 gallons per minute, determine how long it will take to drain the entire tower.
Solution:
Volume = 36000in³
Conversion of in³ to ft³
1 inch = 0.0833 feet
12 inch = 1 ft
1 ft³ = 1ft × 1ft × 1ft
= 12 in x 12 in x 12 in = 1728 in³
36000in³ × [(1ft³)/(1728 in³) = (36000/1728)ft³
= 20.833ft³
Volume = 20.833ft³
There are 7.48 gallons in a cubic foot
In 20.833ft³ = 20.833ft³× (7.48 gallons/1ft³)
= 20.833× 7.48gallons
Volume = 155.83 gallons
The rate of usage = 56 gallons per minute
The rate of usage for 155.83 gallons = 155.83 gallons × (1min/56gallons)
= (155.83/56)minute
= 2.8minutes
Time it will take to drain the entire tower = 2.8minutes
7 - 3 1/4 = (turn mixed number to improper fraction
7 - 13/4 = (common denominator is 4)
28/4 - 13/4 =
15/4 or 3 3/4 gallons remain in the tank