Answer:
b. 0.67
Explanation:
UCL = 1 + 0.10
= 1.10 inch
LCL = 1 - 0.10
= 0.9 inch
standard deviation = 0.005 inch
mean = 1 inch
Cpk
= min[(UCL - mean)/(3*standard deviation) , (mean - LCL)/(3*standard deviation))]
= min[(1.10 - 1)/(3*0.05) , (1 - 0.9)/(3*0.05))]
= min[0.67 , 0.67]
= 0.67
Therefore, Theprocess capability index (Cpk) if the long-run process mean is 1 inch is 0.67
Answer:
The $1,200,000 should be accounted for in Grove’s special revenue funds
Explanation:
Special revenue fund: The special revenue fund is a fund that is introduced by the government to collect the money from the public. It is made to fulfill the need for specific purposes/ projects.
The computation of special revenue funds is shown below:
= Income received for providing the meals to the needy people + financing of sales tax with respect to tourist facilities maintenance in the shopping district
= $300,000 + $900,000
= $1,200,000
Answer:
$277,000
Explanation:
Break even is the point where neither profit nor a loss is made by the company.
<u>Determination of Break-even Sales</u>
Sales - Variable Expenses - Fixed Expenses = 0
Therefore, Solving Algebraically
Sales = Variable Expenses + Fixed Expenses
= 222,000 + 55,000
= 277,000
Therefore Break-even sales for the month for the company is closest to $277,000
Answer:
$1,275
Explanation:
The computation of the amount of commission for paying is shown below:
= Invested amount × fund charges a load percentage
= $30,000 × 4.25%
= $1,275
By multiplying the invested amount with the fund charges a load percentage we can easily calculate the amount of commission and the same is to be considered
Answer and Explanation:
The computation of the service level and the corresponding optimal stocking level is shown below:
Given that
Selling price = SP = $4.50
Cost price = CP = $3.00
So,
Salvage value = V = $1.50
Average daily demand (d) = 35 quarts
The standard deviation of daily demand = 4 quarts
based on the above information
Overage cost = (Co) is
= CP - V
= $3.00 - $1.50
= $1.50
Now
Underage cost= (Cu)
= SP - CP
= $4.50 - $3.00
= $1.50
So,
Service level is
= Cu ÷ (Co + Cu)
= 1.50 ÷ (1.50 + 1.50)
= 1.50 ÷ 3.00
= 0.50
= 50%
Now
At 50 % service level, the value of Z is 0
So,
Optimal stocking level is
= d + Z × standard deviation
= 35 + (0 × 4)
= 35 + 0
= 35 quarts
