Answer:
22.5 miles per hour
Step-by-step explanation:
<u>Given system of equations</u>
5(s-w)=900
4(s+w)=900
<u />
<u>Set equations equal to each other</u>
5(s-w)=4(s+w)
5s-5w=4s+4w
s-5w=4w
s=9w
<u>Solve for w using the substitution s=9w</u>
4(s+w)=900
4(9w+w)=900
4(10w)=900
40w=900
w=22.5
Therefore, the speed of the wind is 22.5 miles per hour
x+7
------------------- =
x^2+4x -21
x+7
= -------------------
(x+7)(x-3)
1
= ---------- where x is not equal -7 and 3
x - 3
answer is A. first choice
The slope is 2, because you subtract the points 3,17 from 7,25 to get 8/4/ Simplify that into 2.
In figure A, you would want to go up 2 and across right 6 to get to A'. In figure 2 you can go up 1 then across right 2.
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the true population mean textbook weight.
Number of sample, n = 22
Mean, u = 64 ounces
Standard deviation, s = 5.1 ounces
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
64 ± 1.645 × 5.1/√22
= 64 ± 1.645 × 1.087
= 64 ± 1.788
The lower end of the confidence interval is 64 - 1.788 = 62.21 ounces
The upper end of the confidence interval is 64 + 1.788 = 65.79 ounces
Therefore, with 90% confidence interval, the true population mean textbook weight is between 62.21 ounces and 65.79 ounces