Large box --> M
Small box --> m
M+m=80
70M+60m=5300
Now solve this system of equations. Very easy job now.
Answer:
The largest integer is 29.
Step-by-step explanation:
Let the consecutive positive integers are x, x+1 and x+2.
The square of sum of squares of three consecutive positive integers is 2354 such that,
It is a quadratic equation whose solution is given by :
x = 27 and x = -29
First positive integer = 27
Second positive integer = 27+1 = 28
Third positive integer = 27+2 = 29
Hence, the largest integer is 29.
Answer:
There are 42 quarters (and 6 dimes).
Step-by-step explanation:
The given ratio is 2:14. But this does not tell us how many dimes nor how many quarters we have. Instead, it's a ratio. Modify this by multiplying numerator and denominator by n and then find n:
Number of dimes 2n
----------------------------- = -----
Number of quarters 14n
Then the total number of coins is 2n + 14n =48, implying that:
16n = 48, or n = 3.
Then the number of dimes is 2(n) = 2(3) = 6, and that of quarters is 14(n) =
14(3) = 42.
There are 42 quarters (and 6 dimes). Notice how the total of 42 and 6 is 48.
Answer:
70 kg
Step-by-step explanation:
Answer:
x<u>></u>17
Step-by-step explanation:
