<h2>1.</h2><h3>1)</h3>
Put the given values of p and q in the factored form equation.
... f(x) = (x -(-1))(x -(-2)) . . . . p and q values put in
... f(x) = (x +1)(x +2) . . . . . . .simplified
<h3>2)</h3>
Multiplying the factors, we have
... f(x) = x(x +2) + 1(x +2) = x² +2x +1x +2
... f(x) = x² +3x +2
<h2>2.</h2>
We want to factor x³ -x² -6x. We notice first of all that x is a factor of all terms. Thus we have
... = x(x² -x -6)
Now, we're looking for factors of -6 that add up to -1. Those are -3 and 2. Thus the factorization is ...
... = x(x -3)(x +2)
<h2>3.</h2>
We want a description of the structure and an equivalent expression for
... 64x⁹ -216
We note that 64, 216, and x⁹ are all cubes, so this expression is ...
... the difference of cubes.
It can be rewritten to
... = 8((2x³)³ -3³)
and so can be factored as
... = 8(2x³ -3)(4x⁶ +6x³ +9)
Answer:
The inequality is;
34°F < t < 71°F
Step-by-step explanation:
Here, using t as the variable, we want to write an inequality
We want to write an inequality above 34 but below 71
The inequality will be;
34°F < t < 71°F
Answer: A = $1503.6
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1000
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
t = 7 years
Therefore,.
A = 1000(1 + 0.06/1)^1 × 7
A = 1000(1.06)^7
A = $1503.6