Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
8. 8.80
9. 90
Step-by-step explanation:
Question 8: Use the Pythagorean formula
DE² = DF²+EF²
EF² = DE² - DF²
= 16.2² - 13.6²
= 77.48
EF = √77.48 = 8.80 (Answer)
Question 9: Use the Cosine Rule
GI² = GH² +HI² - 2·GH·HI·Cos ∠GHI
= 60² + 42² - 2·60·42·Cos 123
= 3600 +1764 - (-2744.98)
= 8108.98
GI = √8108.98 = 90
Answer:
x=2
Step-by-step explanation:
296/21 is the answer hope this helps