The volume of a 5cm cube is 0.5dm*0.5dm*0.5dm = 0.125dm^3
1dm^3 = 1l
So 0.125dm^3 = 125mL
This gives us 2410/125 = 19.28
So the density of gold is 19.28g/mL
Final check: Gold is indeed 19.3g/mL
Explanation:
Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. To attain noble gas configuration it is necessary for the magnesium atom to lose two valence electrons and therefore, it forms ions.
On the other hand, atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. To attain noble gas configuration it needs to gain two electrons. And, on gaining the electrons it forms ions.
Hence, when both magnesium and oxygen ions chemically combine with each other then it forms the compound magnesium oxide ().
This is because magnesium transfer its two valence electrons to the oxygen atom and due to the formation of opposite charges on these atoms they get attracted towards each other.
<span>Celsius scale: 100 degrees.
Fahrenheit scale: 180 degrees.</span>
Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is: