Answer:
4x+5 ft
Step-by-step explanation:
1/2(4x²+29x+30) = 1/2 (x+6) * Height
Height = (4x²+29x+30) / (x+6) = (x+6) (4x+5) / (x+6) = 4x+5
Range, Maximum, and y-intercept
Answer:
26,250 sq mm^2
Step-by-step explanation:
First i cut the shape so its a rectangle on the top and there is a vertical rectangle. Then you find the lengths and to do that for the first rectangle(the horizontal one) you add 75, 75 and 75 to get the length. Then multiply 225(the sum of the 3 75s) by 75 (width) which gets you 16,875.
That is the area of the first rectangle
Now for the vertical rectangle you simply multiply the length and width, 75x125. That equals 9,375. Now add.
9375+16875= 26250!!!!
Answer:
1,3,5
Step-by-step explanation:
81 is a perfect square so it can be written as an integer
11.8 is rational because it can be written as a fraction (107/9)
sqrt(6) isn't a perfect square so it is irrational
3/7 is a fraction so it is rational
8.57 is a terminating decimal so it is rational
Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B%5Cfrac%7B1%7D%7B7%7D%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B1%7D%CF%80%20%3D%202%CF%80)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.
I am joyous to assist you anytime.
