Answer:
680 g/m is the molar mass for the unknown, non electrolyte, compound.
Explanation:
Let's apply the formula for osmotic pressure
π = Molarity . R . T
T = T° absolute (in K)
R = Universal constant gases
π = Pressure
Molarity = mol/L
As units of R are L.atm/mol.K, we have to convert the mmHg to atm
760 mmHg is 1 atm
28.1 mmHg is (28.1 .1)/760 = 0.0369 atm
0.0369 atm = M . 0.082 L.atm/mol.K . 293K
(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M
0.0015 mol/L = Molarity
This data means the mol of solute in 1L, but we have 100mL so
Molarity . volume = mol
0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole
The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m
Answer:
The answer is 42, 39 grams of LiCl
Explanation:
We calculate the weight of 1 mol of LiCl, from the atomic weights of each element obtained from the periodic table:
Weight 1 mol LiCl= Weight Li + Weight Cl =6,94 g+ 35, 45 g= 42, 39grams
Neo-pentane represents the Compound A while compound B is n-pentane.
After careful consideration we can say that compounds A and B are alkanes and also isomers of pentane. In chemistry, Isomers are defined as compounds having same empirical molecular formula but different structural formulas due to varying arrangement of atoms.
Now, as per the question statement, compound A gives a single monochlorination product upon heating with the molecule of chlorine i.e. Cl2 showing that the molecule is extremely symmetric. This molecule must be neo-pentane. Refer to image 1.
Similarly, Compound B forms 3 constitutional isomers after undergoing monochlorination. This compound must be n-pentane since three are 3 different types of carbon atoms in the structure. Refer to image 2.
If you need to learn more about neo-pentane click here:
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RADIATION. Radio waves, microwaves, IR, light, UV, x-rays, GAMMA waves etc are ALL Electromagnetic radiation. The difference between ALL the above is the frequency, I.E. The number of waves per second. The higher the frequency the more energy.
Answer:
because a fruit holds the seeds it needs to reproduce and continue living.