Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
If you mean the slope is m=-2
Well, this is a stem and leaf problem.
The numbers are 20, 28, 29, 29, 31, 32, 36, 41, and 42.
In order to solve for the mean, we find the average and we add the numbers together and divide by 9(there are 9 numbers).
The mean is 32.
The median is the middle number, or 31.
The correct answer is number one
Answer:
below given
Step-by-step explanation:
1) yes
2)no
3)no
4)yes
5)no