Use the following function rule to find f(0). f(x)=3(8)^x + 6 f(0)=

Mathematics

1 answer:

Anestetic [448]1 year ago

6 0

Answer:

Answer: 9

Step-by-step explanation:

${ \tt{f(x) = 3( {8)}^{x} + 6 }}$

• For f(0), substitute x with zero:

${ \tt{f(0) = 3( {8)}^{0} + 6}} \\ \\ { \tt{f(0) = (3 \times 1) + 6}} \\ \\ { \tt{f(0) = 3 + 6}} \\ \\ { \boxed{ \tt{ \: f(0) = 9 \: }}}$

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Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

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Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
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\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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