Answer:
So both equations are true
Step-by-step explanation:
#4 was asking you to substitute x = 4 into both equations to see if it's the solution of the equations.
Substitute x = 4
Ritz equation
y = 30x + 20
y = 30(4) + 20
y = 120 + 20
y = 140
Smits equation:
y = 15x + 80
y = 15(4) + 80
y = 60 + 80
y = 140
Both companies charged same price $140 for 4 days
So both equations are true
Answer:
x = −10 and x = 4
Step-by-step explanation:
x2 + 6x = 40
Subtract 40 from each side
x^2 + 6x -40 =0
Factor, what 2 numbers multiply to -40 and add to 6
10 * -4 = -40 10+-4 = 6
(x+10) (x-4) = 0
Using the zero product property
x+10 =0 x-4=0
x=-10 x=4
Answer:
domain: -2 < x < 4
range: -∞ < y < 9
Step-by-step explanation:
domain: because the domain is all of the x-values, just look for the furthest one to the left, which is -2, and then look for the one that is furthest to the right, it being 4.
range: because the quadratic function has the two arrows continuing downwards, toward the negative portion of the graph, it would be -∞. Then look for the maximum of the graph, which would be considered the most highest part of the graph, which is seen on the graph as 9.
This is problem of ratio and proportion. to solve this, fisrt is calculate the convertion factor.
so the house is 30 feet in actual and 4 in wide on drawing
30 feet / 4 in = 7.5 feet / inso in every inch in the drawing is equivalent to 7.5 feet on actual.
1.2 in ( 7.5 ft/ in) = 9 ft
1.6 in ( 7.5 ft/ in) = 12 ft
