Calleigh should put in 30 pennies
Answer:
all radii of the same circle are congruent
tangents to a circle that intersect are congruent
side CO is congruent to side CO
SSS congruency theorem
Step-by-step explanation:
Step-by-step explanation:
Here
BC=P=10
AC=B=b
AB=H=15
then using fourmula
h^2= p^2+ b^2
b^2= 15×15 - 10× 10
b^2= 125
b=11.2
H has two lines of symmetry
Going vertical and horizontal.
Hope that helped!
Answer:
2 real solutions
Step-by-step explanation:
Get all the terms to one side
10n^2 = 10 - 8n
10n^2 +8n -10 =0
ax^2 +bx+c =0
The discriminant is
b^2 -4ac
8^2 - 4(10)(-10)
64 +400
464
If the discriminant is greater than 0 we have 2 real solutions