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Mathematics

1 answer:

Elan Coil [88]2 years ago

3 0

Answer:

1) 2x^4/343

2) 2x^6/225

3) 2x^12/25

4) 5x^20/16807

Step-by-step explanation:

Hope this helps!

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Write the equation 5x − 2y = 10 in the form y = mx + b. y equals start fraction five over two end fraction x minus 10 y equals s

vaieri [72.5K]

Answer:

y = 5/2x - 5

Step-by-step explanation:

You have to rearrange the equation so that it is equal to y.

5x - 2y = 10

(5x - 2y) - 5x = -5x + 10

-2y = -5x + 10

(-2y)/-2 = (-5x)/-2 + (10)/-2

y = 5/2x - 5

6 0

2 years ago

Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest

Ludmilka [50]

Answer:

$6 \times 10^{7}$

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = $10^{7}$