5. The Riverside Geyser in Yellowstone National Park erupts
1 answer:
Answer:
Step-by-step explanation:
<h3>A.</h3>The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
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Answer:
Step-by-step explanation:
we know that
The right bisector of the line segment JK is a perpendicular line to the segment JK that pass through the midpoint of segment JK
step 1
Find the midpoint JK
The formula to calculate the midpoint between two points is equal to
we have
substitute the values
step 2
Find the slope JK
The formula to calculate the slope between two points is equal to
we have
substitute
step 3
Find the slope of the line perpendicular to the segment JK
we know that
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)
we have
----> slope of segment JK
Find m_2
substitute
step 4
Find the equation for the right bisector of the line segment JK
The equation in point slope form is equal to
we have
substitute
Convert to slope intercept form
isolate the variable y