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3 years ago

List 4 things that can increase the rate of a reaction

2 answers:

5 0

The list of 4 things can increase the rate of a reaction is:
surface area of a solid reactant.
concentration or pressure of a reactant.
temperature.
nature of the reactants.
presence/absence of a catalyst.

Hope this helped :)
Have a great day

KengaRu [80]3 years ago

3 0

-surface area
-catalyst
-concentration
-temperature

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If the volume of a gas at 0.5 atm changes from 150 mL to 75 mL, what is the new pressure?

prisoha [69]

Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

We have

$P_2 = \frac{0.5 \times 150}{75} = \frac{75}{75} = 1 \\$

We have the final answer as

Hope this helps you

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2 years ago

Calculate the boiling temperature of a 0.50 M solution of sucrose. Assume that the concentration is 0.50 m.

Ronch [10]

There is one missing point in the question.

The formula to find an increase in boiling Temperature is :

ΔT = kb x M

ΔT = is the increase in boiling Temperature
Kb = Boiling point constant of the Solvent
M = Molarity

You did not provide the Kb. If you have it, you just have to insert it to the formula to find the ΔT.

And assuming that the other solution is water, you just have to add it up with 100 Celcius

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2 years ago

How is a lithium atom (Li) different from a lithium ion (Li+)

Andrews [41]

A Lithium atom that has lost ONE Electron, is called a Lithium Ion (Li+).

3 0

2 years ago

Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation: 3NO2(g)+H2O(l)→2HNO3(l)+

Vesnalui [34]

Answer:

2 mol NO2

Explanation:

3NO2(g)+H2O(l)→2HNO3(l)+NO(g)

from reaction 3 mol 1 mol

given 11 mol 3 mol

for 3 mol NO2 ----- 1 mol H2O

for x mol NO2 ----- 3 mol H2O

3:x = 1:3

x = 3 *3/1 = 9 mol NO2

So, for 3 mol H2O are needed only 9 mol NO2.

But we have 11 mol NO2. So, NO2 is in excess, and

11 mol NO2 - 9 mol NO2 = 2 mol NO2 will be left after reaction.

3 0

2 years ago

A sample of H2 gas (12.28 g) occupies 100.0 L at 400.0 K and 2.00 atm. A sample weighing 9.49 g occupies ________ L at 353 K and

lutik1710 [3]

Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, you know:

P= 2 atm
V= ?
n= $9.49 gramsx\frac{1 mole}{2 grams} = 4.745moles$ being 2g/mole the molar mass of H2, that is, the amount of mass that a substance contains in one mole.
R= 0.082 $\frac{atmL}{molK}$
T= 353 K

Replacing:

2 atm× V = 4.745 moles× 0.082 $\frac{atmL}{molK}$ × 353 K

Solving:

V = (4.745 moles× 0.082 $\frac{atmL}{molK}$ × 353 K)÷ 2 atm

Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.

Learn more:

brainly.com/question/4147359?referrer=searchResults

5 0

2 years ago