To find this value, simply substitute the number 10 in for x in your equation:
The answer is 98.
Tossing a coin is a binomial experiment.
Now lets say there are 'n' repeated trials to get heads. Each of the trials can result in either a head or a tail.
All of these trials are independent since the result of one trial does not affect the result of the next trial.
Now, for 'n' repeated trials the total number of successes is given by
where 'r' denotes the number of successful results.
In our case and ,
Substituting the values we get,
Therefore, there are 1352078 ways to get heads if a person tosses a coin 23 times.
I think that it is attempt. If i am wrong, sorry.
Answer:
i think so?
Step-by-step explanation:
The probability would be 0.9738.
We first find the z-score for each end of this interval:
z = (x-μ)/(σ/√n) = (100-110)/(18/√49) = -10/(18/7) = -3.89
z = (x-μ)/(σ/√n) = (115-110)/(18/√49) = 5/(18/7) = 1.94
Using a z-table (http://www.z-table.com) we see that the probability that a score is less than the first z-score is 0. The probability under the curve to the left of, less than, the second z-score is 0.9738. Subtracting these we find the area between them:
0.9738 - 0 = 0.9738.