Answer:
it's density must be less than water
law of floatation
wt of the immerged body = wt of the water displaced by it
Positive electric charge and found inside the nucleus
(1) The ball is in the air for <u>1.4 seconds.</u>
(2) The horizontal velocity of the ball as it rolls off the table is<u> 6.32 m/s.</u>
(3) The vertical velocity of the ball right before it hits the ground is <u>13.72 m/s.</u>
(4) The horizontal velocity of the ball right before it hits the ground is<u> 6.32 m/s.</u>
(5) The initial vertical velocity as soon as the ball comes of the cliff is <u>13.72 m/s.</u>
<h3>What is the time of motion of the ball?</h3>
The time of motion of the ball is calculated by applying the following equation.
t = √(2h/g)
where;
- h is the height of the cliff
- g is acceleration due to gravity
t = √(2h/g)
t = √(2 x 9.63 / 9.8)
t = 1.4 seconds
The horizontal velocity of the ball is calculated as follows;
v = d/t
where;
- d is the horizontal distance travelled by the ball = 8.85 m
v = 8.85 m / 1.4 s
v = 6.32 m/s
The vertical velocity of the ball before it hits the ground is calculated as;
vf = vi + gt
vf = 0 + 9.8 x 1.4
vf = 13.72 m/s
The horizontal velocity of the ball right before it hits the ground is calculated as;
the initial velocity of a projectile = final horizontal velocity
vxf = vxi = 6.32 m/s
The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s
Learn more about horizontal velocity here: brainly.com/question/24949996
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If a negative object is used to charge a neutral object, then both objects become charged negatively. In order for the neutral sphere to become negative, it must gain electrons from the negatively charged rod. A metal sphere is electrically neutral. It is touched by a positively charged metal rod.
9514 1404 393
Answer:
1.114 kg/m³
Explanation:
The total mass of the air in the balloon and the balloon + cargo will be the mass of the displaced air. If d is the density of the air in the balloon, then we have ...
2910d +308 = 2910×1.22
Solving for d, we find ...
2910d = 2919(1.22) -308
d = 1.22 -308/2910
d ≈ 1.114 . . . kg/m³
The density of the hot air is about 1.114 kg/m³.