PLEASE HELP!!!!!!!Find the length of the missing sides. Round your answers to the nearest tenth. (Hint: Always make sure to labe
l your triangle first with your reference angle)
1 answer:
Answer:
(9.37, 17.7) ; (14.10, 19.42); (20.8, 22.3)
Step-by-step explanation:
For the first picture :
The missing angle :
180 - (32 + 90)
180 - (122) = 58°
To obtain the length of side x:
From ptthagoras:
Tan58° = opposite / Adjacent
1.6003345 = 15 / x
x = 15 / 1.6003345
= 9.37
y = sqrt(15^2 + 9.37^2)
y = sqrt(312.7969)
y = 17.7m
2)
Missing angle :
From ptthagoras :
Sin54° = opposite / hypotenus
0.8090169 = y/ 24
y = 0.8090169 * 24
y = 19.42
x = sqrt(24^2 - 19.42^2)
x = sqrt(198.8636)
x = 14.10
3)
Sin21° = opposite / hypotenus
0.3583679 = 8 /y
y = 8 / 0.3583679
y = 22.3
x = sqrt(22.3^2 - 8^2)
x = sqrt(433.29)
x = 20.8
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Then it would be 10-5 < 7
so if you solved it it would be 5 < 7
So this statement is true
22 i think idk sorry if i’m wrong
Step-by-step explanation:
Answer:
± 60
Step-by-step explanation:
aₙ = a₁ * rⁿ⁻¹
a₇ = 30 = a₁ * r⁷⁻¹ = a₁ * r⁶ (1)
a₅ = 120 = a₁ * r⁵⁻¹ = a₁ * r⁴ (2)
(1)/(2): 30/120 = 1/4 = r²
r = ± 1/2 or ± 0.5
a₁ = a₇/r⁶ = 30/0.5⁶ = 1920
a₆ = 1920 * (± 1/2)⁶⁻¹ = 1920 * ± 1/32 = ± 60
1/4 * x + 1/4 * 4
(the * are multiplication signs)