All categories

1 year ago

PLSSSSSSS HELPPPP SOMEBODYYYY

Mathematics

1 answer:

Deffense [45]1 year ago

6 0

Answer:

64%

Step-by-step explanation:

there are 16 people aged 21 or under out of a total of 25

$\frac{16}{25} (100)=64$ %

Hope this helps

You might be interested in

Help no links or fake answer or I will report you thanks

likoan [24]

Answer:

Step-by-step explanation:

Given, 

Dimensions of the bed

$= 3in. \: \: by \: \: 2 \frac{2}{3} in. \: \: by \: \: \frac{1}{3} in.$

Therefore, 

Volume of the bed

$= (3 \times 2 \frac{2}{3} \times \frac{1}{3} ) {in}^{3}$

$= (2 \frac{2}{3} \times 1) {in}^{3}$

$= 2 \frac{2}{3} {in}^{3} \: (ans)$

3 0

2 years ago

Let x ∼ bin(9, 0.4). find

Kobotan [32]

A.
$\mathbb P(X>6)=\mathbb P(X=7)+\mathbb P(X=8)+\mathbb P(X=9)$
$=\dbinom97(0.4)^7(1-0.4)^{9-7}+\dbinom98(0.4)^8(1-0.4)^{9-8}+\dbinom99(0.4)^9(1-0.4)^{9-9}$
$\approx0.025$

b.
$\mathbb P(X\ge2)=1-\mathbb P(X$
$=1-\dbinom90(0.4)^0(1-0.4)^{9-0}-\dbinom91(0.4)^1(1-0.4)^{9-1}$
$\approx0.929$

c.
$\mathbb P(2\le X$
$=\dbinom92(0.4)^2(1-0.4)^{9-2}+\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}$
$\approx0.663$

d.
$\mathbb P(2$
$=\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}+\dbinom95(0.4)^5(1-0.4)^{9-5}$
$\approx0.669$

e.
$\mathbb P(X=0)=\dbinom90(0.4)^0(1-0.4)^{9-0}\approx0.01$

f.
$\mathbb P(X=7)=\dbinom97(0.4)^7(1-0.4)^{9-7}\approx0.021$

g, h.
For $X\sim\mathcal B(n,p)$ , recall that $\mathbb 
E[X]=\mu_X=np$ and $\mathbb V[X]={\sigma_X}^2=np(1-p)$ . So

$\mu_X=9(0.4)=3.6$
${\sigma_X}^2=9(0.4)(0.6)=2.16$

6 0

2 years ago

Order the numbers from greatest to least 4.1,4.01,4.009,4.085

nekit [7.7K]

4.1 > 4.01 > 4.085 > 4.009
I hope this helps! ;D

3 0

3 years ago

Read 2 more answers

A bag contains 25 cookies. There are 15 choc. chip , and 7 peanut butter cookies and the rest are oatmeal raisin cookies. What i

stira [4]

Answer:

40 percent