Answer:
4 √6
Step-by-step explanation:
We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:
m²+z² = (8+4)² = 12²
4²+n²=z²
8²+n²=m²
We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.
4²+n²=z²
subtract 4²=16 from both sides
z²-16 = n²
plug that into the third equation
64 + z² - 16 = m²
48 + z² = m²
subtract 48 from both sides to solve for z²
z² = m² - 48
plug that into the first equation
m² + m² - 48 = 144
2m² - 48 = 144
add 48 to both sides to isolate the m² and its coefficient
192 = 2m²
divide both sides by 2 to isolate the m²
96 = m²
square root both sides to solve for m
√96 = m
we know that 96 = 16 * 6, and 16 = 4², so
m = √96 = √(4²*6) = 4 √6
Answer:
40
Step-by-step explanation:
Find the other missing angle, which is supplementary to 100 first.
Supplementary angels are a sum of 180
The missing angle is 180-100 = 80
Now use that to find missing angle x
All angles in the triangle have a sum of 180
180 = 60+80+x
180-60-80=x
40 = x
Answer: About 5 bucks
Step-by-step explanation: Divide 287 by 60 which would equal 4.78333333333
Answer:
10: -11n^5
12: 6k^2 -6k+7
Step-by-step explanation:
Ok so what your gonna do is add or subtract the ones with the same exponent.
so -15+4= -11 since they are both n^5 you can add them so your answer is:
-11n^2
now you have 8k^2-k-5k+7-2k. so you are gonna rearrange them so the same exponents are together.(keep the sign in front in front, if no sign it is positive)
8k^2-2k^2-5k-k+7
add like exponents
6k^2-6k+7
