Answer:
The speed of the first train is 45 mph and the speed of the second train is 75 mph
Step-by-step explanation:
Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).
The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles
The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles
Since the second train overtakes the first at 6:00 pm, hence:
3x + 90 = 5x
2x = 90
x = 45
Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).
Answer:
6 n + 6 b + 1
Step-by-step explanation:
Simplify the following:
11 b - 7 - 3 n + 8 - 5 b + 9 n
Grouping like terms, 11 b - 7 - 3 n + 8 - 5 b + 9 n = (9 n - 3 n) + (11 b - 5 b) + (8 - 7):
(9 n - 3 n) + (11 b - 5 b) + (8 - 7)
9 n - 3 n = 6 n:
6 n + (11 b - 5 b) + (8 - 7)
11 b - 5 b = 6 b:
6 n + 6 b + (8 - 7)
8 - 7 = 1:
Answer: 6 n + 6 b + 1
Answer:
AGE = 129 degrees
Step-by-step explanation:
Answer:
4/25 seconds
Step-by-step explanation:
the second (0.16) is in two decimal places, so divide 16 by 100
to express in the simplest form, divide the numerator and the denominator by 4
=
Salutations!
The temperature changed from 5°C at 6 p.m. to -2°C at midnight. How much did the temperature decrease?
Lets solve this!
To find out how much the temperature is decreased, you need to subtract 5°°C from -2° C. from .
Lets form this into statements ---
Temperature at 6 PM = 5°C
Temperature at midnight = -2°C.
Temperature decreased = 5°C - 2°C = 3° C.
3°C is the temperature decreased.
Hope I helped (:
Have a great day!