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1 year ago

Plants are considered

Chemistry

1 answer:

wariber [46]1 year ago

6 0

Because they create their own food, they are considered as producers.

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A solution is prepared by dissolving 50.0g C6H12O6 in 250g of water. What is the freezing point?

Vedmedyk [2.9K]

50.0g C6H12O6 in 250g

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2 years ago

How many moles of helium gas are contained in a 4.0 L flask at STP

Ratling [72]

First, you convert liters to moles.
Usually you have to go to grams but this is STP.

Get moles directly by dividing the 4 by STP (22.4)
$\frac{4}{22.4} =0.17857142857$
About $1.8*10^{-1}$ or 0.18 moles whichever your teacher prefers

3 0

2 years ago

1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?

RSB [31]

Answer : The number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

$PV=nRT$

where,

P = Pressure of $N_2$ gas = $1.00\times 10^{-6}mmHg=1.32\times 10^{-9}atm$ (1 atm = 760 mmHg)

V = Volume of $N_2$ gas = 985 mL = 0.982 L (1 L = 1000 mL)

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $0.0^oC=273+0.0=273K$

Now put all the given values in above equation, we get:

$(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K$

$n=5.78\times 10^{-11}mol$

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains $6.022\times 10^{23}$ number of molecules.

As, 1 mole of $N_2$ gas contains $6.022\times 10^{23}$ number of molecules

So, $5.78\times 10^{-11}$ mole of $N_2$ gas contains $(5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13}$ number of molecules

Therefore, the number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

8 0

2 years ago

I don't know how to solve this

Misha Larkins [42]

For the first part, use the question M=mol/vol (liters)

To do this, you have the given 1.6 M solution

divide the 360g by the molar mass of ethanol (44.07) to get moles

360/44.07=8.16 mol

1.6M = 8.16 mol/x vol

volume: 5.1 Liters

8 0

2 years ago

Which equation is set up correctly to determine the volume of a 3.2 mole sample of oxygen gas at 50°C and 101.325 kPa?

77julia77 [94]

N = 3.2 moles, T = 50 + 273 = 323 K, P = 101.325 kPa, R = 8.314 L.kPa/K.mol

PV = nRT

V = nRT / P substituting.

V = (3.2 mole)(8.314 L.kPa/K.mol )(323 K) / (<span>101.325 kPa)

That is the answer, but it is not among the options you provided. Check your options properly.</span>

7 0

2 years ago

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