The weight of the third heaviest among the four dogs is 2 kg.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.
Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.
29 + 28 + 2 + 1 = 60 kg
The weight of the third heaviest among the four dogs is 2 kg.
Find out more on equation at: brainly.com/question/2972832
3/4 = .75 so you have to find 75 % of 3/9
100% = 3/9
1% = (3/9)/100
75% = (3/9)/100 * 75 =.25
Answer:
D hope this helps
Step-by-step explanation:
I think 7 mi is the answer
Answer:
C. I & III
Step-by-step explanation:
I simplifies to ...
2(6x +15 -5x) +4 = 40
12x +30 -10x +4 = 40
2x +34 = 40
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II simplifies to ...
40 = 2(15 -x) +4
40 = 30 -2x +4
40 = -2x +34 . . . . . . not equivalent to I (sign of x-term is different)
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III simplifies to ...
12x +30 -10x +4 = 40
2x +34 = 40 . . . . . . equivalent to I
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I & III are equivalent
