<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
Answer:
Step-by-step explanation:
Show the question i cant really see
Answer:
$55,080
Step-by-step explanation:
Hope this helps.
You see how many times 4 can go into 25 witch is 6 not 7 because 7 x 4 is28 and 28is bigger than25 so the answer is and 1/4 is25 cence so the answer is 4.25
Answer:
9<(5+7). the answer is 12
Step-by-step explanation:
hope it helps : )
