$21 I believe (it's 1 am where I am so I'm not 100% sure but I think it's correct)
Answer: i guess the problem is with P(x) => "x = ", then P(x) is true if that equality is true, and is false if the equality is false.
so lets see case for case.
a) x = 0, and = 0. So p(0) is true.
b) x = 1 and = 1, so P(1) is true.
c) x = 2, and = 4, and 2 ≠ 4, then P(2) is false.
d) x= -1 and = 1, and 1 ≠ -1, so P(-1) is false.
By definition of the binomial coefficient,
so we have
as required.
Answer: x^2 -10x + 24
Step-by-step explanation:
(x-6) (x-4)
= x^2 - 6x - 4x + 24
= x^2 -10x + 24
I observe that 5 raised to any whole-number power
produces a number that ends with the digit 5 .