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VladimirAG [237]

1 year ago

11

A parachutists speed during a free fall reaches 180 kilometers per hour. What is this speed in meters per second? At the speed,

how many meters will the parachutes fall during 2 seconds of freefall. Do not round your answers.

1 answer:

Marysya12 [62]1 year ago

7 0

Does this help you at all??

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Y = −4x + 3 <br> Graphing equations in slope-intercept form

jok3333 [9.3K]

Y=-4x+3 is already in slope intercept form. Graphed it looks like this

4 0

2 years ago

Please help me I appreciate

alex41 [277]

Think your answer would be C or D.
it's your choice to decide between those two now.

8 0

2 years ago

What is the area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48

Nesterboy [21]

Answer:

The area of cylinder 949.536 in²

Step-by-step explanation:

Points to remember

Curved surface area of cylinder = 2πrh

Where r - radius of cylinder

h - Height of cylinder

<u>To find the area of cylinder</u>

Here r = diameter/2 = 6.3/2 = 3.15 in

h = 48 in

Area = 2πrh

= 2 * 3.14 * 3.15 * 48

= 949.536 in²

Therefore area of cylinder 949.536 in²

4 0

2 years ago

1. A family went out to dinner, and their food and beverage totaled $51.39. 6% sales tax is added to their bill, and then they p

kompoz [17]

Answer:

62.1819

Step-by-step explanation:

7 0

2 years ago

In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a

nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

$\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ}$ ;

$\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ}$ ;

$\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q$ .

Also,

$\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P$ in right triangle PBM.

Thus $\rm \angle{P\hat{B}M} = \angle C\hat{M}Q$ .

Additionally $\rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}$ .

Therefore $\rm \triangle PBM \sim \triangle MCQ$ .

$\rm \displaystyle BC = 2\;MC$ for M is the midpoint of segment BC.

$\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC$ .

$\rm \triangle PBM \sim \triangle MCQ$ implies that

$\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3$ .

8 0

2 years ago