All categories

2 years ago

13ab+15ab I’m in 6th grade and I need big help

Mathematics

2 answers:

RUDIKE [14]2 years ago

7 0

Answer : 13ab + 15ab= 28ab - simplify

MatroZZZ [7]2 years ago

4 0

$28ab$

Hope it helps

You might be interested in

I NEED HELP PLEASE, THANKS! :)

tekilochka [14]

Answer:

108.43°

Step-by-step explanation:

I graphed this expression on the graph below and found the direction angle of 108.43°.

8 0

2 years ago

Kings Department Store has 625 rubies, 800 diamonds, and 700 emeralds from which they will make bracelets and necklaces that the

Assoli18 [71]

Step-by-step explanation:

Let Xb be the no of braclets made

Let Xn be the no of necklaces made

Max Z=250Xb + 500Xn (Objective Function)

Subject to

2Xb + 5Xn <= 625 (rubies)

3Xb + 7 Xn <= 800 ( diamonds)

4Xb + 3 Xn <= 700 (Emeralds)

Xb>=0 (non-negativity)

Xn >= 0 (non negativity

8 0

2 years ago

Read 2 more answers

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

5 0

2 years ago

Pls helppppp 30 minutes left!! If correct I'll give brainliest to who answers correct first.

anygoal [31]

Answer:

it should be 3.) x+2

Step-by-step explanation:

4 0

2 years ago

For each relation, decide whether or not it is a function<br>

Digiron [165]

Answer:

Relation 1,2,and 4 are functions, but relation 3 not is a function.

Step-by-step explanation:

function 1 input, no function with the same input like m in relation 3.

5 0

2 years ago