Answer:
11.408 joules
Explanation:
soln
From the question above
Mass of ball = m = 1.84kg
Height of ball when dropped = 1.49m
Height of ball when it bounces back up = 0.87m
Recall
Potential energy (P.E) = mass × height × g
Kinetic energy(K.E) = 1/2 × mass × (velocity)²
Mechanical energy = K.E + P.E
M.E lost = M.E when ball dropped – M.E when ball bounces back up
Recall that g = acceleration due to gravity = 10ms²
P.E/K.E when ball dropped = 1.84 × 1.49 × 10
P.E/K.E when ball dropped = 27.416J
P.E/K.E when ball bounces back = 1.84 × 0.87 × 10
P.E /K.Ewhen ball bounces back = 16.008J
Since P.E = K.E
M.E when ball dropped = 27.416J
M.E when ball bounces back = 16.008J
Therefore,
M.E lost = 27.416 - 16.008
M.E lost = 11.408Joules