<u>Formula</u>
<em>An expression that uses variables to state a rule is a </em><u><em>formula</em></u>
<h2>
Explanation:</h2>
An expression that uses variables to state a rule is a formula. It's important to know that formulas uses the equals sign (=) and includes two or more variables. Formulas gives us information that we express symbolically. For example, the well known formula for the volume of a sphere is defined as:
So in this formula we have a relationship between the volume of a sphere and its radius, so if we have information about the radius of it we can easily calculate the volume of it.
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The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
The factored form is (sin x +2)(sin x-1)
Step-by-step explanation:
We have been given the trigonometric function
We can factor this by AC method. In AC method we multiply the term a and c and then write the middle term b in such a way that the sum/difference is equal to the product 'ac'
Using the method, we can write sinx as 2sinx -sinx
Now, we group the first two terms and the last two terms
Now, we take GCF from each group
Factor out (sinx+2)
Therefore, the factored form is (sin x +2)(sin x-1)
The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.
The graph is attached below.
- We are given a quadratic function.
- A polynomial equation of degree two in one variable is a quadratic equation.
- The function given to us is :
- y = x² - 5x - 36
- We need to find the solution of the quadratic function.
- To find the roots, let y = 0.
- x² - 5x - 36 = 0
- Use the quadratic formula.
- In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
- x = [-b±√b²-4ac]/2a
- x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
- x = (5 ± √25 + 144)/2
- x = (5 ± √169)/2
- x = (5 ± 13)/2
- x = 9 or x = -4
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