Assuming that the densities of the gases are:
density of air, ρ1 = 1.29 kg / m^3
density of helium, ρ2 = 0.179 kg / m^3
Since buoyant force and weight are two forces that are in
opposite direction (buoyant force is up while weight is down), therefore equate
the two:
buoyant force = weight
m g = (800 + m1) g
where m is the mass of buoyancy, g is gravity and m1 is
the maximum mass of the cargo
m = 800 + m1
We know that mass is also expressed as:
m = ρ V
where ρ is density of gas and V is volume of the sphere
Since there are two interacting gases here, therefore m
is:
m = (ρ1 – ρ2) V
Therefore:
(ρ1 – ρ2) V = 800 + m1
(1.29 – 0.179) (4π/3) (8.35m)^3 = 800 + m1
2709.33 = 800 + m1
m1 = 1,909.33 kg
Answer:
A) true
33) Osha data : true
34 ) False
Explanation:
A) Karl Landsteiner was the first to classify blood on the basis of modern theory .
33) OSHA ( Occupational Safety and Health Administration ) data relates to the safety measures that are taken by a unit or firm to avoid hazardous situation for their workforce.
34 ) There are as many as 150 points in an average finger prints that can be compared. Some country like England requires 16 point identification , some like France requires 17 points identification. So The statement is wrong.
Answer: A: false
Explanation:
And object will weigh less on the moon because the moons gravity is weaker than Earths gravity.
To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as
The potential energy,
The volume,
The potential energy per unit volume is defined as the energy density.
The energy density related with electric field is given by
Here, the permitivity of the free space is
Therefore, rerranging to find the electric field strength we have,
Therefore the electric field is 2.21V/m
Answer:
A figure skater doing a double axle
The swing of a baseball bat
The leverage on a hockey stick
hope it helps