Answer:
x=1
Step-by-step explanation:
You just have to go through it thoroughly. You are probably making a small mistake somewhere.
1. -4+5x^3-(-3y)^0
-1+-3=-4
3x^2+ 2x^1= 5x^3
9y^1-6y^1=14y^0
2. 2y-(-3x^5)+10
5y-3y=2y
-3x^1+-2x^2=-5x^3
-5x^3+2x^2=-3x^5
3. 3x+3y+8
4x^2+2x=6x^3
6x^3-3x^2=3x
7y-2y=4y
4y-y=3y
-5+(-3)=8
4. 6x^3+4y+2
3x^2+3x^1=6x^3
7y-2y=5y
5y-y=4y
I hope this helped
Answer:
first one is 42/7 = 6
11*6 = 66
second one
1/2 inch = 3/2 feet
17/2 inches = 17*3 = 51/2 = 25.5
Answer:
10 quarters = $2.50
10 nickels = $0.50
that leaves $0.20 for other coins (dimes / pennies)
Step-by-step explanation:
First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.
Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.
This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.
The solution to the given equation is x = ±7. The correct option is d. x = ±7
<h3>Solving quadratic equations </h3>
From the question, we are to determine the solution to the given equation
The given equation is
x²-49 = 0
NOTE: I assumed the variable is x
Solving the equation
x²-49 = 0
Writing in the form ax²= c
x² = 49
∴ x = ±√49
x = ±7
Hence, the solution to the given equation is x = ±7
Learn more on Solving quadratic equations here: brainly.com/question/24334139
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