Oceans one ocean at a time
Answer:
The scale factor is
Step-by-step explanation:
Line segmentAB has vertices A(−3, 4) and B(1, −2) .
A dilation, centered at the origin, is applied to AB. The image has vertices
A'(-1,4/3) and B′(1/3, −2/3) .
We know the rule for dilation by scale factor of k, is
This means that;
But we know, A' has coordinates (-1,4/3)
This means that
We could also compare:
4k=4/3
Which gives
k=⅓
Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Yes Val would have enough time to create 10 slides.
For this case we have that by definition, the point-slope equation of a line is given by:
We have the following points:
We chose a point:
Substituting in the equation we have:
Finally, the equation is:
Answer:
OPTION C