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2 years ago

In what order are chemical elements arranged on the periodic table?

Chemistry

1 answer:

Gala2k [10]2 years ago

3 0

Answer:

an increasng atomic number/ increasing proton count

Explanation:

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Determine % yield if a student obtains 45 g of product in an experiment and the theoretical amount is determined to be 50 g

Katen [24]

Percentage yield=(actual yield/theoretical yield) x 100%
= (45/50) x 100%
= 90%

8 0

3 years ago

Which particle has two positive charge and an electron arrangement of 2, 8?

Fynjy0 [20]

The answer is $Mg^{2+}$ . A magnesium atom has 12 protons and an arrangement of [2, 8, 2]. When you lose two electrons, arrangement becomes [2,8] and the atom becomes a positively charged ion

8 0

2 years ago

Select all that apply.

alexgriva [62]

Hi!

<u>The correct options would be: </u>

is an electron

is emitted from nucleus

has a -1 charge

Explanation:

A beta particle is a result of a neutron (a neutral particle) changing into two particles of opposite charges - a high energy electron (with a negative charge -1) and a positron (with a positive charge +1). Neutrons are present in the nucleus of an atom, and thus the beta particles are said to be emitted from the nucleus. They do have a charge, not zero, but it is not +2 and can only be either -1 or +1. This form of radiation is not electromagnetic energy because beta particles are massless, and do not travel at the speed of light (both being characteristics of electromagnetic radiation). Beta particles are not pure forms of energy.

Hope this helps.

6 0

2 years ago

An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +

Maurinko [17]

Answer:

The simplified expression for the fraction is $\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$

Explanation:

From the given information:

O3* → O3 (1) fluorescence

O + O2 (2) decomposition

O3* + M → O3 + M (3) deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

$\text {X} = \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) } } }$

$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{ {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) } }$

$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3 \times cM) }$

$\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$ since cM is the concentration of the inert molecule

7 0

2 years ago

All energy originates from the ________.

exis [7]

Answer:

Sun is the answer!!!!!!

5 0

2 years ago