Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, is equal to , thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, . Since a and b were generic elements of H, then H/G is abelian.
Answer:
12.496
Step-by-step explanation:
Answer:
A/ 3.14a=b
Step-by-step explanation:
A=3.14ab
Divide each side by 3.14 a to isolate b
A/ 3.14a=3.14ab/3.14a
A/ 3.14a=b
Answer: 13/17
Step-by-step explanation: //Give thanks(and or Brainliest) if helpful (≧▽≦)//
Answer:
B= 44.9506°
Step-by-step explanation:
WE apply sine angle formula
Given angle C = 51, c= 11 and b = 10
Plug in the values
Cross multiply it
10 * sin(51) = 11* sin(B)
7.771459615 = 11 sin(B)
Now divide by 11 on both sides
0.706496328 = sin(B)
Now
B= 44.9506°