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1 year ago

Pls help me :"( geometry i will give brainliest and 100 Pts

Mathematics

1 answer:

dalvyx [7]1 year ago

4 0

<u>Answer:</u>

ΔLNM is proved as isosceles triangle. Below for explanation.

<u>Step-by-step explanation:</u>

We know that:

AMBX = Square
Squares have equal sides

Since AMBX is a square, AL must equal to BN because they are the extra lengths of the square. The lengths of the square are AM, MB, BX, XA.

Side of square + Extra length = Side of triangle

This can tell us that the two sides of the triangle are equal. We also know that if 2 sides of a triangle are equal, it is classified as an isosceles triangle. Hence, ΔLNM is proved as an isosceles triangle.

Hoped this helped!

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I'd really appreciate it if anyone helped! :) Giving Brainliest!

Anna11 [10]

the first three are irrational

5 0

2 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

masha68 [24]

Answer:

○ $\displaystyle 0 + 2kπ$

Explanation:

<em>See above</em><em> </em><em>explanation</em>

I am joyous to assist you anytime.

5 0

2 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

SOMEONE HELP ME!! NO ONE WILL HELP T^T WILL MARK BRAINLIEST

Anastasy [175]

Answer: nope!

Step-by-step explanation: there are 4 quarts in a gallon and we can see by adding the mango juice, there will be no space!

Water (2 quarts) mango juice (2 quarts) equals a gallon

Ginger ale = one gallon

That’s already 2 gallons and we still have the 2 pints of pineapple juice!

7 0

2 years ago

The perimeter of a rectangle is 160 meters. The length is 20 meters greater than the width. Find the dimensions of the rectangle

s344n2d4d5 [400]

<h2><em>Width=w </em></h2><h2><em>Length=l </em></h2><h2><em>Perimeter=p </em></h2><h2><em> </em></h2><h2><em>p=2w+2l </em></h2><h2><em>l=20+w </em></h2><h2><em>p=2w+20+w+20+w </em></h2><h2><em>p=4w+40 </em></h2><h2><em> </em></h2><h2><em>4w+40=160 </em></h2><h2><em>4w=160-40=120 </em></h2><h2><em>w=120:4=30 </em></h2><h2><em>w=30 </em></h2><h2><em>l=20+w </em></h2><h2><em>l=20+30=50</em></h2>

4 0

3 years ago