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1 year ago

7

Find the area of a semi circle with a diameter of 28cm

1 answer:

Alexandra [31]1 year ago

8 0

since it has a diameter of 28, then its radius must be half that or 14.

$\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }$

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True or false the opposite sides of a kite are never parallel

Rasek [7]

Answer: True

If the opposite sides were parallel, then you would have a parallelogram (which isn't a kite). A parallelogram has opposite sides that are congruent.

A kite is a figure with adjacent sides that are congruent. A kite does not have opposite sides that are congruent.

6 0

2 years ago

The diagram below shows part of the graph of y=g(x) .

son4ous [18]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

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2 years ago

Mr. Washington is buying a gallon of milk for $3.99 and some boxes of cereal for $4.39 each. If Mr. Washington has

wolverine [178]

Answer:

$20-$3.99(milk)=$17.01÷$4.39(cereal)=4 boxes of cereal

5 0

2 years ago

A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?

zzz [600]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf 240 \: {inches}^{2} }}}}$

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

$\boxed{ \sf{perimeter = 2(l + w)}}$

plug the values

⇒ $\sf{64 = 2(20 + w)}$

Distribute 2 through the parentheses

⇒ $\sf{64 = 40 + 2w}$

Swap the sides of the equation

⇒ $\sf{40 + 2w = 64}$

Move 2w to right hand side and change it's sign

⇒ $\sf{2w = 64 - 40}$

Subtract 40 from 64

⇒ $\sf{2w = 24}$

Divide both sides of the equation by 2

⇒ $\sf{ \frac{2w}{2} = \frac{24}{2} }$

Calculate

⇒ $\sf{w = 12 \: inches}$

Width of a rectangle ( w ) = 12 inches

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

$\boxed{ \sf{area \: of \: rectangle = length \: \times \: \: width}}$

plug the values

⇒ $\sf{area \: of \: rectangle =20 \times 12 }$

Multiply the numbers : 20 and 12

⇒ $\sf{area \: of \: rectangle = 240 \: {inches}^{2} }$

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0

2 years ago

Help please someone

kenny6666 [7]

Answer: step by step explanation

it's just that you have to multiply the number under root and it's any number is square then you can take it out of root.

4 0

2 years ago